smallest 3 digit number divisible by 6 8 12|Determinethe smallest 3 : Tuguegarao SOLUTION : First find the LCM of 6,8,12. LCM by prime factorization method : 6 = 2¹ × 3¹. 8 = 2³. 12 = 2² × 3. LCM (6,8,12) = 2³ × 3¹ = 8 × 3 = 24. [Product of the greatest power of each prime factor .
In this chapter, you will study numerical and graphical ways to describe and display your data. This area of statistics is called "Descriptive Statistics." You will learn how to calculate, and even more importantly, how to .
smallest 3 digit number divisible by 6 8 12,Thus, all the multiples of 24 will also be divisible by 6, 8, and 12. Now we will divide the smallest 3-digit number with the LCM obtained, and the remainder will be subtracted from the dividend, and 24 will be added to it to make it perfectly divisible.smallest 3 digit number divisible by 6 8 12We have to find the smallest $$3$$-digit multiple of $$24$$. It can be seen that $$24\times 4=96$$ and $$24\times 5=120$$. Hence, the smallest $$3$$-digit number which is .Determinethe smallest 3We have to find the smallest $$3$$-digit multiple of $$24$$. It can be seen that $$24\times 4=96$$ and $$24\times 5=120$$. Hence, the smallest $$3$$-digit number which is .smallest 3 digit number divisible by 6 8 12 Determinethe smallest 3We have to find the smallest $$3$$-digit multiple of $$24$$. It can be seen that $$24\times 4=96$$ and $$24\times 5=120$$. Hence, the smallest $$3$$-digit number which is .
So, the smallest three digit multiple of 24 will be, 100 = (100 – 4) + 24 = 96 + 24 = 120. Hence, the smallest 3-digit number which is exactly divisible by 6, 8, and 12, is 120. . The smallest 3-digit number which is exactly divisible by 6, 8, and 12 is 120. In Mathematics, the LCM is the value which is evenly divisible by the given two .LCM of 6, 8 and 12 = 2×2×2×3 = 24. The smallest 3-digit number = 100. To find the smallest 3-digit number possible we have to look for smallest 3-digit multiples of 24. .
SOLUTION : First find the LCM of 6,8,12. LCM by prime factorization method : 6 = 2¹ × 3¹. 8 = 2³. 12 = 2² × 3. LCM (6,8,12) = 2³ × 3¹ = 8 × 3 = 24. [Product of the greatest power of each prime factor . Determinethe smallest 3-digit number which is exactly divisible by 6, 8 and 12.Class: 6Subject: MATHSChapter: PLAYING WITH NUMBERSBoard:CBSEYou can . Therefore, the smallest 3-digit number divisible by 6, 8, and 12 is 120. Summary: - Prime factorization of 6: 2 * 3 - Prime factorization of 8: 2 * 2 * 2 - Prime . Hence, the smallest 3-digit number which is exactly divisible by 6, 8 and 12 is 120. This is the required answer. Note: In such types of questions it is always advisable .
Smallest number = LCM of 6, 8, 12. We have to find the smallest 3-digit multiple of 24. It can be seen that. 24 4 = 96 and. 24 5 = 120. Hence, the smallest 3-digit number which .
Smallest number = LCM of 6, 8, 12. We have to find the smallest 3-digit multiple of 24. It can be seen that. 24 4 = 96 and. 24 5 = 120. Hence, the smallest 3-digit number which .
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